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CGP EDU Academic Team
Published on: September 12, 2026
One thousand small water drops of equal radii combine to form a big drop. The ratio of final surface energy to the total initial surface energy is
Text Solution
Verified by ExpertsThe correct answer is:
D
As volume remain constant therefore $R = n^{1/3} r$
$\frac{\text{surface energy of one big drop}}{\text{surface energy of n drop}} = \frac{4 \pi R^{2} T}{n \times 4 \pi r^{2} T} \\ \frac{R^{2}}{n r^{2}} = \frac{n^{2/3} r^{2}}{n r^{2}} = \frac{1}{n^{1/3}} = \frac{1}{(1000)^{1/3}} = \frac{1}{10}$
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